PHP实现两种排课方式

2023-02-16 22:19:35 IOS开发

两种排课方式：

固定每周的固定时间上课（例：共上20节，每周六、周日早上8点-10点上课。假如今天周六凌晨1点，那么排课也需要从今天开始）总共上几个周，每周上课时间比较个性化（例：共上三周，第一周周一周二早上8点-10点上课；第二周周三周四下午8点-10点上课；第三周周日中午11点-12点上课。）

第一种排课比较好实现，简要代码如下：

/**
     * 生成日期列表
     *
     * @param  int $startDate 开始日期 时间戳格式
     * @param  array $timeList 课时计划列表
       [
        {
            "start_at": "09:09", //开课时间
            "end_at": "10:09",   //结束时间
            "week_at": 1         //周几
        },
        {
            "start_at": "12:09", //开课时间
            "end_at": "13:09",   //结束时间
            "week_at": 1         //周几
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 5
        }
       ]
     * @param  int $amount 课时计划数量
     * @param  int $skipHoliday 跳过节假日
     *
     * @return array
     */
    public function generateDateList($startDate, $timeList, $amount, $skipHoliday = 0)
    {
        // 计算开始日期是周几
        $startDateWeek = intval(date('N', $startDate));
 
        //规范化课时数据 week_at 做key的三维数组
        foreach ($timeList as $item) {
 
            $weekAt = $item['week_at'];
            
            array_splice($item, 0, 0, $weekAt);
            $key = array_shift($item);
            $weeksTime[$key][] = $item;
            $item = null;
        }
 
        unset($timeList);
 
        if (empty($weeksTime)) {
            $this->addError('课时计划数据为空');
            return false;
        }
 
        //设置跳过假期,获取开始日期之后的节假日
        if ($skipHoliday) {
            $holiday = new Holiday();
            $holidayData = $holiday->getHolidayList($startDate);
            $holiday = null;
            unset($holiday);
        }
 
        $nowTime = time();
        $list = array();
 
        for ($weekStartTime = $startDate, $count = 0; $count < $amount; $weekStartTime += 86400 * 7) {
 
            //$currentWeek :周几
            foreach ($weeksTime as $currentWeek => $weekTime) {
 
                foreach ($weekTime as $time) {
 
                    //算出对应的日期时间戳
                    $currentDateTime = $weekStartTime + (($startDateWeek <= $currentWeek ? ($currentWeek - $startDateWeek) : (7 - $startDateWeek + $currentWeek)) * 86400);
                    //对应的日期 = 开始时间 + ((开始时间对应周 <= 数据对应的周几 ？ (数据对应的周几 - 开始时间对应周) ：（7 - 开始时间对应周 + 数据对应的周几）) * 86400)
                    //假期跳过排课
                    if ($skipHoliday && !empty($holidayData)) {
                        $startUnix = $currentDateTime + $time['start_at'] * 3600;  //开始时间
                        $endUnix = $currentDateTime + $time['end_at'] * 3600;     //结束时间
 
                        $skip = false;
 
                        //选择跳过节假日，且节假日与当前课程时间有重叠跳过
                        foreach ($holidayData as $item) {
                            if (($item['start_at'] < $endUnix && $item['end_at'] > $startUnix) || ($item['start_at'] === $startUnix && $item['end_at'] === $endUnix)) {
                                $skip = true;
                                continue;
                            }
                        }
 
                        if ($skip) {
                            continue;
                        }
                    }
 
                    $currentDate = date('Y/m/d', $currentDateTime);
                    $startAt = strtotime($currentDate . $time['start_at'] . ':00');
                    $endAt = strtotime($currentDate . $time['end_at'] . ':00');
 
                    if($startAt < $nowTime || $endAt < $nowTime){
                        $this->addError('上课时间不能小于当前时间');
                        return false;
                    }
 
                    $list[] = [
                        'date_at' => $currentDateTime, //日期
                        'week_at' => $currentWeek,     //周几
                        'start_at' => $startAt,
                        'end_at' => $endAt
                    ];
 
                    $count++;
 
                    if ($count >= $amount) {
                        break 3;
                    }
                }
            }
        }
 
        $weeksTime = null;
        unset($weeksTime);
 
        return $list;
    }

（例子，只用来展示数据结构）假如总共5节课时，从6-25日开始排课，每周一、周六上课：

PHP实现两种排课方式(图1)

（例子，只用来展示数据结构）排课结果为：

PHP实现两种排课方式(图2)

第二种排课方式稍微麻烦一点，简要代码如下：

/**
     * 生成日期列表
     *
     * @param  int $startDate 开始日期 时间戳格式
     * @param  array $taskList 任务列表
    [
        {
            "start_at": "09:09", //开始上课时间
            "end_at": "10:09",   //结束时间
            "week_at": 1,        //周几
            "week_number": 1     //第几周
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 2,
            "week_number": 1
        },
        {
            "start_at": "09:09",
            "end_at": "10:09",
            "week_at": 1,
            "week_number": 3
        }
    ]
     *
     * @return array
     */
    public function generateDateList($startDate, $taskList)
    {
        // 计算开始日期是周几
        $startDateWeek = intval(date('N', $startDate));
 
        $list = [];
        $nowTime = time();
        $weekSign = $week = 0;
 
        foreach($taskList as $key => $task){
 
            if($task['week_number'] > $weekSign && $task['week_number'] != $week){
                $weekSign = $task['week_number'] - $week;
            }
 
            //计算每条数据对应的日期 $key == 0：确定第一周第一节课是在本周还是下一周
            if($key == 0 || $task['week_number'] == $week){
 
                if($task['week'] >= $startDateWeek){
                    $task['date_at'] = $startDate +
                        (($weekSign - 1) * 7 + ($task['week'] - $startDateWeek)) * 86400;
                }else{
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
                }
            }else{
                if($task['week'] > $startDateWeek){
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 + ($task['week'] - $startDateWeek)) * 86400;
                }else{
                    $task['date_at'] = $startDate +
                        (($weekSign) * 7 - ($startDateWeek - $task['week'])) * 86400;
                }
            }
 
            $startDateWeek = intval(date('N', $task['date_at']));
 
            $week = $task['week_number'];
 
            $startDate = $task['date_at'];
 
            $dateAt = date('Y/m/d', $task['date_at']);
 
            $startAt = strtotime($dateAt . '00:00:00');
            if($task['start_at']){
                $startAt = strtotime($dateAt . $task['start_at'] . ':00');
            }
 
            $endAt = strtotime($dateAt . '23:59:59');
            if($task['end_at']){
                $endAt = strtotime($dateAt . $task['end_at'] . ':00');
            }
 
            if($startAt < $nowTime || $endAt < $nowTime){
                $this->addError('上课时间不能小于当前时间');
                return false;
            }
 
            $task['start_at'] = $startAt;
            $task['end_at'] = $endAt;
 
            //生成课时数据
            $list[] = [
                    'date_at' => $task['date_at'],
                    'week_at' => $task['week'],
                    'start_at' => $startAt,
                    'end_at' => $endAt
                ];
        }
 
        return $list;
    }

（例子，只用来展示数据结构）排课数据：

PHP实现两种排课方式(图3)